Integrand size = 30, antiderivative size = 93 \[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=-\frac {a^2 \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f (1+n p)}+\frac {2 a^2 \operatorname {Hypergeometric2F1}(1,1+n p,2+n p,i \tan (e+f x)) \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f (1+n p)} \]
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Time = 0.28 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {1600, 1970, 81, 66} \[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=-\frac {a^2 \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f (n p+1)}+\frac {2 a^2 \tan (e+f x) \operatorname {Hypergeometric2F1}(1,n p+1,n p+2,i \tan (e+f x)) \left (c (d \tan (e+f x))^p\right )^n}{f (n p+1)} \]
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Rule 66
Rule 81
Rule 1600
Rule 1970
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\left (c (d x)^p\right )^n (a+i a x)^2}{1+x^2} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\text {Subst}\left (\int \frac {\left (c (d x)^p\right )^n (a+i a x)}{\frac {1}{a}-\frac {i x}{a}} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\left (\tan ^{-n p}(e+f x) \left (c (d \tan (e+f x))^p\right )^n\right ) \text {Subst}\left (\int \frac {x^{n p} (a+i a x)}{\frac {1}{a}-\frac {i x}{a}} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {a^2 \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f (1+n p)}+\frac {\left (2 a \tan ^{-n p}(e+f x) \left (c (d \tan (e+f x))^p\right )^n\right ) \text {Subst}\left (\int \frac {x^{n p}}{\frac {1}{a}-\frac {i x}{a}} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {a^2 \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f (1+n p)}+\frac {2 a^2 \operatorname {Hypergeometric2F1}(1,1+n p,2+n p,i \tan (e+f x)) \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f (1+n p)} \\ \end{align*}
Time = 0.87 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.62 \[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=\frac {a^2 (-1+2 \operatorname {Hypergeometric2F1}(1,1+n p,2+n p,i \tan (e+f x))) \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{f+f n p} \]
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\[\int \left (c \left (d \tan \left (f x +e \right )\right )^{p}\right )^{n} \left (a +i a \tan \left (f x +e \right )\right )^{2}d x\]
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\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=\int { {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{2} \left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n} \,d x } \]
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\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=- a^{2} \left (\int \left (- \left (c \left (d \tan {\left (e + f x \right )}\right )^{p}\right )^{n}\right )\, dx + \int \left (c \left (d \tan {\left (e + f x \right )}\right )^{p}\right )^{n} \tan ^{2}{\left (e + f x \right )}\, dx + \int \left (- 2 i \left (c \left (d \tan {\left (e + f x \right )}\right )^{p}\right )^{n} \tan {\left (e + f x \right )}\right )\, dx\right ) \]
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\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=\int { {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{2} \left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n} \,d x } \]
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\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=\int { {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{2} \left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n} \,d x } \]
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Timed out. \[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^2 \, dx=\int {\left (c\,{\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^p\right )}^n\,{\left (a+a\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^2 \,d x \]
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